Resposta
$W = nRT \ln\left(\frac{V_2}{V_1}\right) = nRT \ln\left(\frac{P_1}{P_2}\right)$.
Explicação
Since temperature is constant, $\Delta U = 0$ for an ideal gas, meaning all absorbed heat equals work done ($Q = W$).
Início / Biblioteca / JEE Main Master Class: Calculus, Mechanics, Coordinate Geometry / Flashcard sintético
What is the expression for work done in an isothermal expansion of $n$ moles of ideal gas from $V_1$ to $V_2$ at temperature $T$?
Flashcard de estudo do deck JEE Main Master Class: Calculus, Mechanics, Coordinate Geometry.