Resposta
$B = \frac{\mu_0 I}{2R}$.
Explicação
Along the central axis at distance $x$ from the loop plane, the field is $B = \frac{\mu_0 I R^2}{2(R^2 + x^2)^{3/2}}$.
Início / Biblioteca / JEE Main Master Class: Calculus, Mechanics, Coordinate Geometry / Flashcard sintético
What is the magnetic field $B$ at the center of a circular current loop of radius $R$ carrying current $I$?
Flashcard de estudo do deck JEE Main Master Class: Calculus, Mechanics, Coordinate Geometry.