Resposta
$I = \frac{1}{2} M R^2$.
Explicação
For a thin hoop/ring, $I = M R^2$; for a uniform solid sphere, $I = \frac{2}{5} M R^2$; for a thin spherical shell, $I = \frac{2}{3} M R^2$.
Início / Biblioteca / JEE Main Master Class: Calculus, Mechanics, Coordinate Geometry / Flashcard sintético
What is the moment of inertia of a uniform solid cylinder/disk of mass $M$ and radius $R$ about its central symmetry axis?
Flashcard de estudo do deck JEE Main Master Class: Calculus, Mechanics, Coordinate Geometry.