Antwort
$\text{pH} = -\log_{10}[\text{H}^+]$ and $\text{pH} + \text{pOH} = 14.0$ at 25°C.
Erklärung
Pure water at 25°C has $[\text{H}^+] = 1.0 \times 10^{-7} \text{ M}$, corresponding to a neutral pH of 7.0.
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How is pH defined in an aqueous solution, and what is the relation between pH and pOH at 25°C ($K_w = 1.0 \times 10^{-14}$)?
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