Antwort
$N(t) = N_0 e^{-\lambda t}$, with half-life $T_{1/2} = \frac{\ln 2}{\lambda} \approx \frac{0.693}{\lambda}$.
Erklärung
Activity is defined as $A = |\frac{dN}{dt}| = \lambda N = A_0 e^{-\lambda t}$, measured in Becquerels (Bq).
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What is radioactive decay law for the number of undecayed nuclei $N(t)$ with decay constant $\lambda$?
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