Antwort
$I = \frac{1}{2} M R^2$.
Erklärung
For a thin hoop/ring, $I = M R^2$; for a uniform solid sphere, $I = \frac{2}{5} M R^2$; for a thin spherical shell, $I = \frac{2}{3} M R^2$.
Start / Bibliothek / JEE Main Master Class: Calculus, Mechanics, Coordinate Geometry / Synthetische Lernkarte
What is the moment of inertia of a uniform solid cylinder/disk of mass $M$ and radius $R$ about its central symmetry axis?
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