Answer
$a_n = a_1 \cdot r^{n-1}$; Infinite sum $S_\infty = \frac{a_1}{1 - r}$ for $|r| < 1$.
Explanation
If $|r| \geq 1$, the infinite series diverges and has no finite sum.
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$a_n = a_1 \cdot r^{n-1}$; Infinite sum $S_\infty = \frac{a_1}{1 - r}$ for $|r| < 1$.
If $|r| \geq 1$, the infinite series diverges and has no finite sum.