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What is the period $T$ of a simple harmonic oscillator with mass $m$ attached to a spring of spring constant $k$?
Study flashcard from the deck JEE Main Master Class: Calculus, Mechanics, Coordinate Geometry.
Answer
$T = 2\pi \sqrt{\frac{m}{k}}$ and angular frequency $\omega = \sqrt{\frac{k}{m}}$.
Explanation
For a simple pendulum of length $L$ in uniform gravity $g$, $T = 2\pi \sqrt{\frac{L}{g}}$ for small amplitude oscillations ($\sin\theta \approx \theta$).
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