Answer
$B = \frac{\mu_0 I}{2R}$.
Explanation
Along the central axis at distance $x$ from the loop plane, the field is $B = \frac{\mu_0 I R^2}{2(R^2 + x^2)^{3/2}}$.
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What is the magnetic field $B$ at the center of a circular current loop of radius $R$ carrying current $I$?
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