Answer
$\eta = 1 - \frac{T_C}{T_H} = \frac{T_H - T_C}{T_H}$.
Explanation
No real engine operating between the two reservoirs can exceed the Carnot efficiency limit stipulated by the Second Law of Thermodynamics.
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What is the efficiency $\eta$ of an ideal Carnot heat engine operating between temperatures $T_H$ and $T_C$ in Kelvin?
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