Answer
$y = a(x - h)^2 + k$, where the vertex is located at $(h, k)$ and the axis of symmetry is $x = h$.
Explanation
If $a > 0$, the parabola opens upward and $k$ is the minimum value; if $a < 0$, it opens downward and $k$ is the maximum value.
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$y = a(x - h)^2 + k$, where the vertex is located at $(h, k)$ and the axis of symmetry is $x = h$.
If $a > 0$, the parabola opens upward and $k$ is the minimum value; if $a < 0$, it opens downward and $k$ is the maximum value.