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For f(x) = x^3 - 3x, at which x-values is the tangent line horizontal?

Study flashcard from the deck CSAT (Suneung) essentials: original practice.

Answer

At x = -1 and x = 1.

Explanation

The derivative is f'(x) = 3x^2 - 3. Setting it to zero gives x^2 = 1, so the slope is zero at x = -1 and x = 1.

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