Respuesta
Parabola: $e = 1$; Ellipse: $e = \sqrt{1 - \frac{b^2}{a^2}} < 1$ ($a > b$); Hyperbola: $e = \sqrt{1 + \frac{b^2}{a^2}} > 1$.
Explicación
Eccentricity measures the degree of deviation of a conic section from circularity ($e = 0$).
Inicio / Biblioteca / JEE Main Master Class: Calculus, Mechanics, Coordinate Geometry / Flashcard sintético
Flashcard de estudio del mazo JEE Main Master Class: Calculus, Mechanics, Coordinate Geometry.
Parabola: $e = 1$; Ellipse: $e = \sqrt{1 - \frac{b^2}{a^2}} < 1$ ($a > b$); Hyperbola: $e = \sqrt{1 + \frac{b^2}{a^2}} > 1$.
Eccentricity measures the degree of deviation of a conic section from circularity ($e = 0$).