Respuesta
$P(A|B) = \frac{P(B|A)P(A)}{P(B)}$.
Explicación
By law of total probability, the denominator can be expressed as $P(B) = P(B|A)P(A) + P(B|A^c)P(A^c)$.
Inicio / Biblioteca / CSAT (Suneung) essentials: original practice / Flashcard sintético
Flashcard de estudio del mazo CSAT (Suneung) essentials: original practice.
$P(A|B) = \frac{P(B|A)P(A)}{P(B)}$.
By law of total probability, the denominator can be expressed as $P(B) = P(B|A)P(A) + P(B|A^c)P(A^c)$.