解答
$v_o = \sqrt{\frac{GM}{R}} = \sqrt{gR}$; Escape velocity $v_e = \sqrt{\frac{2GM}{R}} = \sqrt{2} v_o \approx 11.2\text{ km/s}$.
解説
Escape velocity is obtained by equating total mechanical energy $E = \frac{1}{2}mv^2 - \frac{GMm}{R}$ to zero.
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What are the orbital velocity $v_o$ and escape velocity $v_e$ from the surface of Earth ($M, R$)?
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