解答
$c^2 = a^2 + b^2 - 2ab\cos C$.
解説
When $C = 90^\circ$, $\cos 90^\circ = 0$, reducing the law of cosines to the Pythagorean theorem $c^2 = a^2 + b^2$.
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$c^2 = a^2 + b^2 - 2ab\cos C$.
When $C = 90^\circ$, $\cos 90^\circ = 0$, reducing the law of cosines to the Pythagorean theorem $c^2 = a^2 + b^2$.