解答
At x = -1 and x = 1.
解説
The derivative is f'(x) = 3x^2 - 3. Setting it to zero gives x^2 = 1, so the slope is zero at x = -1 and x = 1.
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For f(x) = x^3 - 3x, at which x-values is the tangent line horizontal?
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