정답
$\text{pH} = -\log_{10}[\text{H}^+]$ and $\text{pH} + \text{pOH} = 14.0$ at 25°C.
해설
Pure water at 25°C has $[\text{H}^+] = 1.0 \times 10^{-7} \text{ M}$, corresponding to a neutral pH of 7.0.
홈 / 라이브러리 / Gaokao essentials: original practice / AI 플래시카드
How is pH defined in an aqueous solution, and what is the relation between pH and pOH at 25°C ($K_w = 1.0 \times 10^{-14}$)?
덱 'Gaokao essentials: original practice'의 플래시카드.