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JEE Main Master Class: Calculus, Mechanics, Coordinate Geometry

Rigorous problem-solving deck for JEE Main Paper 1 covering differential and integral calculus, conic sections, rotational mechanics, and modern physics.

20 flashcards · 감수: Ada

문제 2: What is Leibniz's rule for differentiating an integral with variable limits ddx∫u(x)v(x)f(t) dt\frac{d}{dx} \int_{u(x)}^{v(x)} f(t)\,dt?

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정답

ddx∫u(x)v(x)f(t) dt=f(v(x))⋅v′(x)−f(u(x))⋅u′(x)\frac{d}{dx} \int_{u(x)}^{v(x)} f(t)\,dt = f(v(x)) \cdot v'(x) - f(u(x)) \cdot u'(x).

Widely tested in JEE Main calculus questions involving limits of the form 00\frac{0}{0} evaluated using L'Hôpital's Rule.

문제 4: What is the general solution to the first-order linear differential equation dydx+P(x)y=Q(x)\frac{dy}{dx} + P(x)y = Q(x)?

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y⋅e∫P(x)dx=∫Q(x)⋅e∫P(x)dx dx+Cy \cdot e^{\int P(x)dx} = \int Q(x) \cdot e^{\int P(x)dx}\,dx + C, where IF=e∫P(x)dx\text{IF} = e^{\int P(x)dx} is the integrating factor.

Multiplying by the integrating factor transforms the left side into the exact derivative ddx(y⋅IF)\frac{d}{dx}(y \cdot \text{IF}).

문제 10: What are the orbital velocity vov_o and escape velocity vev_e from the surface of Earth (M,RM, R)?

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정답

vo=GMR=gRv_o = \sqrt{\frac{GM}{R}} = \sqrt{gR}; Escape velocity ve=2GMR=2vo≈11.2 km/sv_e = \sqrt{\frac{2GM}{R}} = \sqrt{2} v_o \approx 11.2\text{ km/s}.

Escape velocity is obtained by equating total mechanical energy E=12mv2−GMmRE = \frac{1}{2}mv^2 - \frac{GMm}{R} to zero.

문제 12: What is the adiabatic gas relation for an ideal gas undergoing a reversible quasi-static process?

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PVγ=constantP V^\gamma = \text{constant}, TVγ−1=constantT V^{\gamma - 1} = \text{constant}, and P1−γTγ=constantP^{1-\gamma} T^\gamma = \text{constant}, where γ=CpCv\gamma = \frac{C_p}{C_v}.

For a monoatomic ideal gas, γ=53≈1.67\gamma = \frac{5}{3} \approx 1.67; for a diatomic gas, γ=75=1.40\gamma = \frac{7}{5} = 1.40.

문제 16: What is the standard limit lim⁡x→0sin⁡xx\lim_{x \to 0} \frac{\sin x}{x} and lim⁡x→0ex−1x\lim_{x \to 0} \frac{e^x - 1}{x}?

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lim⁡x→0sin⁡xx=1\lim_{x \to 0} \frac{\sin x}{x} = 1 and lim⁡x→0ex−1x=1\lim_{x \to 0} \frac{e^x - 1}{x} = 1.

Also lim⁡x→01−cos⁡xx2=12\lim_{x \to 0} \frac{1 - \cos x}{x^2} = \frac{1}{2} and lim⁡x→∞(1+1x)x=e\lim_{x \to \infty} \left(1 + \frac{1}{x}\right)^x = e.

문제 17: What is Rolle's Theorem and the Lagrange Mean Value Theorem (LMVT)?

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LMVT states that if ff is continuous on [a,b][a, b] and differentiable on (a,b)(a, b), there exists c∈(a,b)c \in (a, b) such that f′(c)=f(b)−f(a)b−af'(c) = \frac{f(b) - f(a)}{b - a}.

Rolle's theorem is the special case where f(a)=f(b)f(a) = f(b), guaranteeing at least one stationary point where f′(c)=0f'(c) = 0.

문제 18: How is vector cross product a⃗×b⃗\vec{a} \times \vec{b} computed using components?

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a⃗×b⃗=det⁡(i^j^k^a1a2a3b1b2b3)\vec{a} \times \vec{b} = \det \begin{pmatrix} \hat{i} & \hat{j} & \hat{k} \\ a_1 & a_2 & a_3 \\ b_1 & b_2 & b_3 \end{pmatrix}, resulting in a vector perpendicular to both a⃗\vec{a} and b⃗\vec{b}.

Magnitude is ∣a⃗×b⃗∣=∣a⃗∣∣b⃗∣sin⁡θ|\vec{a} \times \vec{b}| = |\vec{a}||\vec{b}|\sin\theta, representing the area of the parallelogram formed by the vectors.

문제 20: What is the condition for an extremum (local minimum or maximum) of a function f(x)f(x) using second derivatives?

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정답

If f′(c)=0f'(c) = 0 and f′′(c)>0f''(c) > 0, f(c)f(c) is a local minimum; if f′(c)=0f'(c) = 0 and f′′(c)<0f''(c) < 0, f(c)f(c) is a local maximum.

If f′′(c)=0f''(c) = 0, the test is inconclusive and higher derivatives or sign changes of f′(x)f'(x) must be examined.