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홈 / 라이브러리 / JEE Main Master Class: Calculus, Mechanics, Coordinate Geometry / AI 플래시카드

What is the Bohr formula for the energy of an electron in the $n$-th orbit of a hydrogen-like atom of atomic number $Z$?

덱 'JEE Main Master Class: Calculus, Mechanics, Coordinate Geometry'의 플래시카드.

정답

$E_n = -13.6 \frac{Z^2}{n^2}\text{ eV}$.

해설

The orbital radius scales as $r_n = 0.529 \frac{n^2}{Z}\text{ \AA}$, and electron velocity scales as $v_n = 2.18 \times 10^6 \frac{Z}{n}\text{ m/s}$.

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